| | 1 | '''2013年9月13,9.20日代码道场活动纪实'''[[BR]] |
| | 2 | [[BR]] |
| | 3 | '''代码道场的参与者''':秦鸿源,陈阳,王安宁,丁健勇,李炳岳,黄志强,李剑文,张艺辉,江毅超, 李峰[[BR]] |
| | 4 | [[BR]] |
| | 5 | '''地点''':4G会议室[[BR]] |
| | 6 | [[BR]] |
| | 7 | 回顾一下,上一期,我们做了购书活动的扩展,将下面的几种折扣方案进行比较,哪种最优惠,就有哪种方案结帐。 |
| | 8 | {{{ |
| | 9 | 单集购买5本,优惠7元。 |
| | 10 | 支持买6送1活动。 |
| | 11 | 支持购买100元送10活动。 |
| | 12 | }}} |
| | 13 | 考虑到,实际生活中,商场有时也会进行一些折上折的促俏活动,所以,我们将再一次对购书活动的促俏方式进行扩展 |
| | 14 | [[BR]] |
| | 15 | 我们按照顺序,依次对上面几种促销方案,进行折扣,最后计算出总价 |
| | 16 | [[BR]] |
| | 17 | 我们设计折上折的促俏方案类为Best2Calculator,它实现了PriceCalculator接口。 |
| | 18 | [[BR]] |
| | 19 | 我们对各个方案组合开发了测试代码,如下: |
| | 20 | {{{ |
| | 21 | package cn.pconline.harrypotter; |
| | 22 | |
| | 23 | import static org.junit.Assert.*; |
| | 24 | |
| | 25 | import java.util.ArrayList; |
| | 26 | import java.util.List; |
| | 27 | |
| | 28 | import org.junit.Before; |
| | 29 | import org.junit.Test; |
| | 30 | |
| | 31 | public class Best2CalculatorTest { |
| | 32 | private List<Book> books = null; |
| | 33 | private Best2Calculator best2Calculator = null; |
| | 34 | private Book book1 = new Book(BookType.one); |
| | 35 | private Book book2 = new Book(BookType.two); |
| | 36 | private Book book3 = new Book(BookType.three); |
| | 37 | private Book book4 = new Book(BookType.four); |
| | 38 | private Book book5 = new Book(BookType.five); |
| | 39 | private Book book6 = new Book(BookType.six); |
| | 40 | private Book book7 = new Book(BookType.seven); |
| | 41 | |
| | 42 | @Before |
| | 43 | public void setup() { |
| | 44 | books = new ArrayList<Book>(); |
| | 45 | best2Calculator = new Best2Calculator(); |
| | 46 | } |
| | 47 | |
| | 48 | |
| | 49 | /** |
| | 50 | * 测试无满足方案(只买一本) |
| | 51 | * @throws Exception |
| | 52 | */ |
| | 53 | @Test |
| | 54 | public void testCalculate0() throws Exception { |
| | 55 | books.add(book1); |
| | 56 | int price = best2Calculator.calculate(books); |
| | 57 | assertEquals(800, price); |
| | 58 | } |
| | 59 | |
| | 60 | /** |
| | 61 | * //满足1种方案 |
| | 62 | */ |
| | 63 | @Test |
| | 64 | public void testCalculate1() { |
| | 65 | //只满足第1种方案,多集少于5本,一共少于7本 |
| | 66 | books.add(book1); |
| | 67 | books.add(book2); |
| | 68 | books.add(book3); |
| | 69 | int price = best2Calculator.calculate(books); |
| | 70 | assertEquals(3 * 800 * 90/100 ,price); |
| | 71 | |
| | 72 | //只满足第2种方案,单集只买5-6本 |
| | 73 | books.clear(); |
| | 74 | for (int i=0; i<5; i++) { |
| | 75 | books.add(book1); |
| | 76 | } |
| | 77 | price = best2Calculator.calculate(books); |
| | 78 | assertEquals(5 * 800 - 700, price); |
| | 79 | |
| | 80 | books.add(book1); |
| | 81 | price = best2Calculator.calculate(books); |
| | 82 | assertEquals(6 * 800 - 700, price); |
| | 83 | |
| | 84 | //只满足第3种方案不存在 |
| | 85 | |
| | 86 | //只满足第4种方案不存在 |
| | 87 | } |
| | 88 | |
| | 89 | |
| | 90 | |
| | 91 | /** |
| | 92 | * 满足2种方案 |
| | 93 | */ |
| | 94 | @Test |
| | 95 | public void testCalculate2(){ |
| | 96 | //(单集5本,另有1集1本)符合方案1,方案2 |
| | 97 | |
| | 98 | for (int i=0; i<5; i++) { |
| | 99 | books.add(book1); |
| | 100 | } |
| | 101 | books.add(book2); |
| | 102 | int price = best2Calculator.calculate(books); |
| | 103 | assertEquals(6 * 800 * 95/100 - 700, price); |
| | 104 | |
| | 105 | //(7-12本,单集不能等于或大于5本)符合方案1,方案3 |
| | 106 | books.clear(); |
| | 107 | for (int i = 0; i < 4; i++) { |
| | 108 | books.add(book1); |
| | 109 | } |
| | 110 | |
| | 111 | for(int i = 0; i < 3; i++) { |
| | 112 | books.add(book3); |
| | 113 | } |
| | 114 | |
| | 115 | price = best2Calculator.calculate(books); |
| | 116 | assertEquals(7 * 800 * 95/100 - 800, price); |
| | 117 | |
| | 118 | //等于12本,单集不能等于或大于5本 |
| | 119 | books.clear(); |
| | 120 | for (int i = 0; i < 4; i++) { |
| | 121 | books.add(book2); |
| | 122 | } |
| | 123 | |
| | 124 | for (int i = 0; i < 4; i++) { |
| | 125 | books.add(book5); |
| | 126 | } |
| | 127 | |
| | 128 | for (int i = 0; i < 4; i++) { |
| | 129 | books.add(book3); |
| | 130 | } |
| | 131 | |
| | 132 | price = best2Calculator.calculate(books); |
| | 133 | assertEquals(12 * 800 * 90 / 100 - 800, price); |
| | 134 | |
| | 135 | //符合方案1,方案4,没有这种方案 |
| | 136 | |
| | 137 | //符合方案2,方案3, |
| | 138 | books.clear(); |
| | 139 | for (int i = 0; i < 7; i++) { |
| | 140 | books.add(book3); |
| | 141 | } |
| | 142 | price = best2Calculator.calculate(books); |
| | 143 | assertEquals(800 * 7 - 700 - 800, price); |
| | 144 | //符合方案2,方案4,没有这种方案 |
| | 145 | |
| | 146 | //符合方案3,方案4,没有这种方案 |
| | 147 | } |
| | 148 | |
| | 149 | /** |
| | 150 | * 满足3种方案 |
| | 151 | */ |
| | 152 | @Test |
| | 153 | public void testCalculate3(){ |
| | 154 | //符合方案1,方案2,方案3 |
| | 155 | // 买7 本,一集买2本,二集买5本 |
| | 156 | int price = 0; |
| | 157 | books.clear(); |
| | 158 | for (int i = 0; i < 5; i++) { |
| | 159 | books.add(book2); |
| | 160 | } |
| | 161 | books.add(book1); |
| | 162 | books.add(book1); |
| | 163 | |
| | 164 | price = best2Calculator.calculate(books); |
| | 165 | assertEquals(800 * 7 * 95 / 100 - 700 - 800, price); |
| | 166 | |
| | 167 | //符合方案1,方案2,方案4,没有这种方案 |
| | 168 | |
| | 169 | //符合方案1,方案3,方案4 |
| | 170 | //买19本,四集各买4本,一集买3本 |
| | 171 | books.clear(); |
| | 172 | for (int i = 0; i < 4; i++) { |
| | 173 | books.add(book1); |
| | 174 | books.add(book2); |
| | 175 | books.add(book3); |
| | 176 | books.add(book4); |
| | 177 | } |
| | 178 | books.add(book5); |
| | 179 | books.add(book5); |
| | 180 | books.add(book5); |
| | 181 | price = best2Calculator.calculate(books); |
| | 182 | assertEquals(800 * 19 * 80 / 100 - (800 * 2) - 1000, price); |
| | 183 | |
| | 184 | //符合方案2,方案3,方案4 |
| | 185 | /* |
| | 186 | * 单集18本 |
| | 187 | * |
| | 188 | * (18 * 800) - (3 * 700) - (2 * 800) = 10700 |
| | 189 | * 所以单集18本满足方案2,3,4 |
| | 190 | */ |
| | 191 | books.clear(); |
| | 192 | for (int i = 0; i < 18; i++) { |
| | 193 | books.add(book1); |
| | 194 | } |
| | 195 | |
| | 196 | price = best2Calculator.calculate(books); |
| | 197 | assertEquals(((18 * 800) - (3 * 700) - (2 * 800) - 10 * 100), price); |
| | 198 | } |
| | 199 | |
| | 200 | /** |
| | 201 | * 满足4种方案 |
| | 202 | */ |
| | 203 | @Test |
| | 204 | public void testCalculate4(){ |
| | 205 | //符合全部方案 |
| | 206 | /*买18本,买两集分别为9本 |
| | 207 | * (18 * 800 * 95 / 100 - (2 * 700) - (2 * 800)) |
| | 208 | */ |
| | 209 | |
| | 210 | for (int i = 0; i < 9 ; i++) { |
| | 211 | books.add(book1); |
| | 212 | books.add(book2); |
| | 213 | } |
| | 214 | int price = best2Calculator.calculate(books); |
| | 215 | assertEquals((18 * 800 * 95 / 100 - (2 * 700) - (2 * 800) - 10 * 100) , price); |
| | 216 | |
| | 217 | } |
| | 218 | } |
| | 219 | |
| | 220 | }}} |
| | 221 | Best2Calculator实现代码如下 |
| | 222 | {{{ |
| | 223 | package cn.pconline.harrypotter; |
| | 224 | |
| | 225 | import java.util.List; |
| | 226 | |
| | 227 | public class Best2Calculator implements PriceCalculator { |
| | 228 | |
| | 229 | @Override |
| | 230 | public int calculate(List<Book> list) { |
| | 231 | if (list == null || list.isEmpty()) { |
| | 232 | return 0; |
| | 233 | } |
| | 234 | //方案1 |
| | 235 | PriceCalculator pc1 = new DefaultCashier(); |
| | 236 | //方案2 |
| | 237 | PriceCalculator pc2 = new DiscountCashier(); |
| | 238 | //方案3 |
| | 239 | PriceCalculator pc3 = new SendBookActivity(); |
| | 240 | //方案4 |
| | 241 | PriceCalculator pc4 = new SendMoneyActivity(); |
| | 242 | //没打折的总价 |
| | 243 | int tempPrice = list.size() * 800; |
| | 244 | |
| | 245 | int currentPrice = 0; // 保存当前价钱 |
| | 246 | |
| | 247 | currentPrice = tempPrice - (tempPrice - pc1.calculate(list)); |
| | 248 | |
| | 249 | currentPrice = currentPrice - (tempPrice - pc2.calculate(list)); |
| | 250 | |
| | 251 | currentPrice = currentPrice - (tempPrice - pc3.calculate(list)); |
| | 252 | |
| | 253 | if (currentPrice >= 1000) { |
| | 254 | currentPrice = currentPrice - (currentPrice / 10000) * 1000; |
| | 255 | } |
| | 256 | |
| | 257 | |
| | 258 | |
| | 259 | return currentPrice; |
| | 260 | } |
| | 261 | |
| | 262 | } |
| | 263 | |
| | 264 | }}} |
| | 265 | 销售哈里波特书籍这个题目,真的很不错,我们从实现最基本功能到实现各种促俏方案,从易到难,循序渐进,[[BR]] |
| | 266 | 我们做了好几期,大家都有收获,大家一起讨论,团队协作能力有一定的提高。对单元测试有了更深的理解,对大家养成单元测试的习惯,有了很大的促进作用。[[BR]] |
| | 267 | 中间,我们使用模拟测试的技术,让新同事耳目一新。[[BR]] |
| | 268 | |